When you are combining Copper (II) Oxide with Sulfuric Acid, would you need to keep the '2' in Cu when working with Cu2O + H2SO4? I don't really know how else to word my question.

The (II) shows the valence state of the copper, By writing Cu2O you have shown the valence state as Oxygen has a fixed valence, so it is no longer necessary.

Is this what you were asking?

Not exactly. I'm just trying to figure out how I would combine copper (II) oxide with sulfuric acid. The only thing I'm not sure of is whether I am supposed to keep the subscripts when combining them or not.

The subscripts show the amount of each atom in the molecule. In Cu2O there are 2 copper atoms and an oxygen atom.

I still don't quite understand what you mean by "keeping" it

When I am trying to predict the products, would it be Cu2SO4 + H2O, or would it be CuSO4 + OH, or what? Does that make sense?

Yes sort of. You don't need to keep the number, no, as long as there are an equal amount of each atom on each side, to make it a balanced reaction.

You have to work out what the products are through chemical knowledge, then balance the equation to make the numbers right.

Thanks for all your help.

*tips hat*